Matematyka

prosze o rozwiazanie tych zadan w zalaczniku

Odpowiedź

tallaaxd

Do drugiego załącznika a) Z pitagorasa 4^{2} + x^{2} = 10^{2} x^{2} = 100 - 16 x^{2} = 84 x = [latex]4sqrt{6}[/latex] [latex]P_{p}[/latex] = [latex]4^{2}[/latex] [latex]P_{p}[/latex] = 16 [latex]P_{b}[/latex] = [latex]frac{4 * 4sqrt{6}}{2} *4[/latex] [latex]P_{b}[/latex] = [latex]32sqrt{6}[/latex] [latex]P_{c}[/latex] = 16 + 32[latex]sqrt{16}[/latex] V = [latex] frac{1}{3}[/latex] * [latex]P_{c}[/latex] * H Wpierw musimy wysokość obliczyć z pitagolasa;] [latex]H^{2} + (2sqrt{2})^{2} = 10^{2} [/latex] H^{2} + 8 = 100 H^{2} = 100 - 8 H = [latex]2sqrt{3} [/latex] V = [latex] frac{1}{3} [/latex] * 16 * [latex]2sqrt{23}[/latex] V = [latex]frac{32sqrt{23}}{3}[/latex] b) [latex]P_{p}[/latex] = [latex] frac{a *h}{2}[/latex] [latex]P_{p}[/latex] = [latex]frac{6 * 3sqrt{3}}{2}[/latex] [latex]P_{p}[/latex] = 3 * [latex]3 sqrt{3}[/latex] [latex]P_{p}[/latex] = 9[latex]sqrt{3}[/latex] Teraz z Pitagorasa [latex]3^{2} + x^{2} = 9^{2} [/latex] [latex]9 - x^{2} = 81 [/latex] [latex]81 -9 = x^{2} [/latex] x = [latex]6sqrt{3}[/latex] [latex]P_{bh}[/latex] = [latex]frac{6sqrt{3} * 3 * 6}{2}[/latex] [latex]P_{b}[/latex] = 54[latex]sqrt{2}[/latex] P[latex]P_{c}[/latex] = [latex]54 sqrt{2} + 9sqrt{3}[/latex] V = [latex]frac{1}{3} * 9sqrt{3} * sqrt{96}[/latex] V = [latex]3sqrt{207}[/latex] V = [latex]9sqrt{23}[/latex] c) [latex]P_{p}[/latex] = [latex]6 * frac{a^{2}sqrt{3}}{4}[/latex] [latex]P_{p}[/latex] = [latex]6 * frac{2^{2}sqrt{3}}{4}[/latex] [latex]P_{p}[/latex] = 6[latex]sqrt{3}[/latex] Znowu z pitagorasa [latex]1^{2} + h^{2} = 6^{2}[/latex] [latex]36 - 1 = h^{2}[/latex] h = [latex]sqrt{35}[/latex] [latex]P_{b}[/latex] = [latex]6 * frac{1}{2} * 2 * sqrt{35}[/latex] [latex]P_{b}[/latex] = 6[latex]sqrt{35} [/latex] [latex]P_{c}[/latex] = [latex]6sqrt{3} + 6sqrt{35}[/latex] Znowy trzeba z Pitagorasa [latex]H^{2} + 2^{2} = 6^{2}[/latex] H = [latex]4sqrt{2}[/latex] --- > odrazu ci wynik podałem bo chyba potęgowanie umiesz V = [latex]frac{1}{3} * 6sqrt{35} * 8sqrt{6}[/latex] I to tyle wszystko powinno być dobrze;] A z tamtymi kątami to ci nie pomogę bo nie wiem;] Jak pomogłem daj naj!;]

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Chemia

Siemanko, prosze o rozwiazanie tych zadan w zalaczniku Z gory dziekii :D

Siemanko, prosze o rozwiazanie tych zadan w zalaczniku Z gory dziekii :D...

Chemia