Oblicz: 1. log ₁₀ = 2. log ₇1= 3. log ₀,₅2√2= 4. log ₀,₁∛0,01= 5. log ₀,₃ 0,09 =   Oblicz: 1. log ₅x=2 2. log ₃x=-1 3. log ₂x=½ 4. log ½x= -5 5. log ₁₀x= -½ 6. log ₃x= ⅔ 

Oblicz: 1. log ₁₀ 10=1 2. log ₇1=0 3. log ₀,₅2√2=-3/2 4. log ₀,₁∛0,01=2/3 5. log ₀,₃ 0,09 =2   Oblicz: 1. log ₅x=2=> 5^2=x => x=25 2. log ₃x=-1=> 3^(-1)=x => x=1/3 3. log ₂x=½=> 2^1/2=x => x=√2 4. log ½x= -5=> 1/2^(-5)=x => x=2^5 => x=32 5. log ₁₀x= -½=> 10^(-1/2)=x => x=√10 6. log ₃x= ⅔=> 3^2/3=x => x=[latex]sqrt[3]{3^{2}}[/latex] => x=[latex]sqrt[3]{9}[/latex]  

Oblicz: a) 2 log 3 + 3 log 2= b) 3 log 4 - 4 log 2= c) 2 log √3 + 3 log 1= d) log log log log 10¹⁰ = e) log₃ 6 + log₃ √0,75 = f) log₄(3+log₃(1+log₂ 4))= g) log₄(1+log₄(2+log₄16))=

Oblicz: a) 2 log 3 + 3 log 2= b) 3 log 4 - 4 log 2= c) 2 log √3 + 3 log 1= d) log log log log 10¹⁰ = e) log₃ 6 + log₃ √0,75 = f) log₄(3+log₃(1+log₂ 4))= g) log₄(1+log₄(2+log₄16))=...

Oblicz. a) log 8+log 125 b) log₇ 19-log₇ ¹⁹/₄₉ c) log 6-log 2-log 3 d) log ⁷/₄-log 14-log125 Wiadomo, że logx=¹/₃ oblicz: a) log x⁶ b) log ¹/x³ c) log pierwiastek z x d log ¹/pierwiastek z x do potęgi 3 Proszę o szybką odpowiedź naprawdę ważne

Oblicz. a) log 8+log 125 b) log₇ 19-log₇ ¹⁹/₄₉ c) log 6-log 2-log 3 d) log ⁷/₄-log 14-log125 Wiadomo, że logx=¹/₃ oblicz: a) log x⁶ b) log ¹/x³ c) log pierwiastek z x d log ¹/pierwiastek z x do potęgi 3 Proszę o...

oblicz: log₂ √2 l og₃ ³√3=⅓ log₄ ⁵√16=5 log₃ ³√9 log₂ √½ log₅ ⁵√25 log₅ 5√5 log₉ 3³√3 log₃ 54+log₃ 1,5 log₂ 144-log₂ 9 log₂ 5+ log₂ 5,6 2log₃ 6-log₃ 4 log₄ 20-log₄ 5 log₅ 0,5+2log₅ 20- 3log₅ 2 log20 - log2 log40-log40000

oblicz: log₂ √2 l og₃ ³√3=⅓ log₄ ⁵√16=5 log₃ ³√9 log₂ √½ log₅ ⁵√25 log₅ 5√5 log₉ 3³√3 log₃ 54+log₃ 1,5 log₂ 144-log₂ 9 log₂ 5+ log₂ 5,6 2log₃ 6-log₃ 4 log₄ 20-log₄ 5 log₅ 0,5+2log₅ 20...

Oblicz: [latex]a) log_{6} 2+ log_{6} 18 \ b) log_{5} 20- log_{5} 4 \ c) log_{} 40+2 log_{} 5 \ d) log_{2} 12+ log_{2}3- log_{2} 9[/latex]

Oblicz: [latex]a) log_{6} 2+ log_{6} 18 \ b) log_{5} 20- log_{5} 4 \ c) log_{} 40+2 log_{} 5 \ d) log_{2} 12+ log_{2}3- log_{2} 9[/latex]...

Oblicz: log [16} 2 = log [0,5] 32 = log [√2] 6 + 2 log [√2] 2 - log [√2] 3 = log [9] 15 - log [9] 20/3 + 2 log [9] 6 = log [8] √2 =

Oblicz: log [16} 2 = log [0,5] 32 = log [√2] 6 + 2 log [√2] 2 - log [√2] 3 = log [9] 15 - log [9] 20/3 + 2 log [9] 6 = log [8] √2 =...

oblicz; a) log₂√2+log₃9-log½4 b) log₃27-log½√2+log₃⅓ c) log125+log4-log5 d) log₃36-log₃2+log₃⅙ e) log₇19-log₇ ¹⁹/₄₉

oblicz; a) log₂√2+log₃9-log½4 b) log₃27-log½√2+log₃⅓ c) log125+log4-log5 d) log₃36-log₃2+log₃⅙ e) log₇19-log₇ ¹⁹/₄₉...