Oblicz: [latex]a) log_{6} 2+ log_{6} 18 \ b) log_{5} 20- log_{5} 4 \ c) log_{} 40+2 log_{} 5 \ d) log_{2} 12+ log_{2}3- log_{2} 9[/latex]

Oblicz: [latex]a) log_{6} 2+ log_{6} 18 \ b) log_{5} 20- log_{5} 4 \ c) log_{} 40+2 log_{} 5 \ d) log_{2} 12+ log_{2}3- log_{2} 9[/latex]
Odpowiedź

A) log6_2+log6_18=log6_2+log6_3+1=log6_2*3+1=1+1=2 b) log5_20-log5_4=log5_(20/4)=log5_5=1 c)log40+2log5=log40+log25=log100=2 d)log2_12+log2_3-log2_9=2+log2_3*3-log2_9=2

[latex]a) hspace{3} log_{6}2+log_{6}18=log_{6}2+log_{6}3+1=log_{6}2*3+1=1+1=2 [/latex] [latex]b) hspace{3} log_{5}20-log_{5}4=log_{5}(frac{20}{4})=log_{5}5=1[/latex] [latex]c) hspace{3}log40+2log5=log40+log25=log100=2[/latex] [latex]d) hspace{3} log_{2}12+log_{2}3-log_{2}9=2+log_{2}(3*3)-log_{2}9=2[/latex]

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