Zadanie wykonam w załączniku
Oblicz x: * log[latex]_{x} [/latex] (2x+3)=0 * log[latex]_{x} [/latex] 125=3 * log[latex]_{x} [/latex] [latex] frac{1}{25} [/latex]=-2 * log[latex]_{(2x-5)} [/latex]16=2 *log[latex] sqrt{3-x} [/latex]0,25=-2
Oblicz x: * log[latex]_{x} [/latex] (2x+3)=0 * log[latex]_{x} [/latex] 125=3 * log[latex]_{x} [/latex] [latex] frac{1}{25} [/latex]=-2 * log[latex]_{(2x-5)} [/latex]16=2 *log[latex] sqrt{3-x} [/latex]0,25=-2...
1. Oblicz: 1) [latex] log_{ sqrt{2} } 2 sqrt{2} [/latex] 2. Oblicz podstawę logarytmu: 1) [latex]log_{a}2 = frac{1}{2} [/latex] 2) [latex] log_{a}8=6 [/latex] 3)[latex] log_{a}32=-5 [/latex] Proszę o pomoc :P
1. Oblicz: 1) [latex] log_{ sqrt{2} } 2 sqrt{2} [/latex] 2. Oblicz podstawę logarytmu: 1) [latex]log_{a}2 = frac{1}{2} [/latex] 2) [latex] log_{a}8=6 [/latex] 3)[latex] log_{a}32=-5 [/latex] Proszę o pomoc :P...
Oblicz : [latex]log_{2} 8[/latex] [latex]log_{2} 16[/latex] [latex]log_{2} 4[/latex] [latex]log_{2} 2[/latex] [latex]log_{2} 1[/latex] [latex]log_{2} sqrt{2} [/latex] [latex]log_{5} frac{1}{5} [/latex] [latex]log_{5} 5[/latex] [latex]log 1[/late
Oblicz : [latex]log_{2} 8[/latex] [latex]log_{2} 16[/latex] [latex]log_{2} 4[/latex] [latex]log_{2} 2[/latex] [latex]log_{2} 1[/latex] [latex]log_{2} sqrt{2} [/latex] [latex]log_{5} frac{1}{5} [/latex] [latex]log_{5} 5[/latex] [latex]log 1...
Oblicz X. a) [latex]log frac{1}{4} x = -2[/latex] b) [latex]log sqrt{2} x = 6[/latex] c) [latex]log 0,04 x = -frac{1}{2} [/latex]
Oblicz X. a) [latex]log frac{1}{4} x = -2[/latex] b) [latex]log sqrt{2} x = 6[/latex] c) [latex]log 0,04 x = -frac{1}{2} [/latex]...
Oblicz. b) [latex](log_{2} frac{1}{8} - log_{3} frac{3}{2} + log_{3} 4,5)^{log_sqrt{2}}4} [/latex]
Oblicz. b) [latex](log_{2} frac{1}{8} - log_{3} frac{3}{2} + log_{3} 4,5)^{log_sqrt{2}}4} [/latex]...