Zad1. Uporządkuj jednomiany : 3x - 7xy = -2*(-3)*a*a*b = a^2*4*b*b= b^2*b*(-2)= zad2. zapisz w prostszej postaci: 15xy/5= 2bd^2/d^2= 4ab^2/ab^2= zad3. Zapisz w jak najprostszej postaci: x+4+(2x-6)= x^2+2x+1-(x^2-4x+3)= (4x-y)+(2x+y-7)=

[latex]Zad.1 \ 3x - 7xy =-21x^2y \ -2*(-3)*a*a*b =6a^2b \ a^2*4*b*b=4a^2b \ b^2*b*(-2)=-2b^3 \ \ Zad.2 \ dfrac{15xy} {5}=3xy \ dfrac{2bd^2}{d^2}=2b \ dfrac{4ab^2}{ab^2}=4 \ \ Zad.3 \ x+4+(2x-6)=x+4+2x-6=3x-2 \ x^2+2x+1-(x^2-4x+3)=\ x^2+2x+1-x^2+4x-3=6x-2 \ (4x-y)+(2x+y-7)=4x-y+2x+y-7=6x-7 \ 3a+b-(5a-2b)=3a+b-5a+2b=-2a+3b \ \ Zad.4 \ 3x(x-7)=3x^2-21 \ a^2(a+2b-1)=a^3+2a^2b-a^2\ (2a+b)*c=2ac+bc \ 5(x-z)=5x-5z \ (2x+4xy):2=x+2xy \ [/latex] [latex](10a+5b-15):(-5)=-2a-b+3 \ (6a-9ab+1):(-3)=-2a+3ab- frac{1}{3} [/latex]