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Matematyka

Oblicz: [latex]a) log_{8} [ log_{4} ( log_{2} 16)] \ \ b) log_{2}(4+ log_{2}16) \ \ c) log_{1,2} 1frac{91}{125} \ \ d) 5^{3- log_{5}2 } \ \ e) 5^{2- log_{5}9 } - 3^{-1+ log_{3}18 } \ \ f) (frac{1}{3} )^{ log_{3} 7} [/latex]

Oblicz: [latex]a) log_{8} [ log_{4} ( log_{2} 16)] \ \ b) log_{2}(4+ log_{2}16) \ \ c) log_{1,2} 1frac{91}{125} \ \ d) 5^{3- log_{5}2 } \ \ e) 5^{2- log_{5}9 } - 3^{-1+ log_{3}18 } \ \ f) (frac{1}{3} )^{ log_{3} 7} [/latex]
Odpowiedź

Log(12)4+ log(12)36= log(12)4*36= log(12) 144=12 log (2/5) 40 + log(2/5) 1/100= log(2/5) 40*1/100= log(2/5)4/10= 1 log(4)40+log(4)1/5=log(4)40*1/5=log(4)8=3/2 log(5)3-log(5)15=log(5)3/15= log(5)1/5= -1 log(4/9)8-log(4/9)27=log(4/9)= 8/27= 3 log(8)48-log8(3)=log(8)48/3= log(8)16= log(1,5)3+log(1,5)0,5=log(1,5)3/0,5= log(1,5)6 log(9)54-log(9)2=log(9)54/2= log(9) 27=3 log(0,5)24+log(0,5)1/3=log(0,5) 24*3= log(0,5) 72

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Matematyka

Oblicz: [latex]a) log_{8} [ log_{4} ( log_{2} 16)] \ \ b) log_{2}(4+ log_{2}16) \ \ c) log_{1,2} 1frac{91}{125} \ \ d) 5^{3- log_{5}2 } \ \ e) 5^{2- log_{5}9 } - 3^{-1+ log_{3}18 } \ \ f) (frac{1}{3} )^{ log_{3} 7}[/latex]

Oblicz: [latex]a) log_{8} [ log_{4} ( log_{2} 16)] \ \ b) log_{2}(4+ log_{2}16) \ \ c) log_{1,2} 1frac{91}{125} \ \ d) 5^{3- log_{5}2 } \ \ e) 5^{2- log_{5}9 } - 3^{-1+ log_{3}18 } \ \ f) (frac{1}{3} )^{ log_{3} 7}[/latex]...