Oblicz ile ciepla trzeba dostarczyc 10kg lodu o temperaturze -10*C, aby zmienic go w wodę o temperaturze +10*C Cw=4200J/kg*C Ct=335000J/kg Cwl= 2100J/kg*C DAM NAJ :)))))))))))))))

[latex]Cw = frac{delta Q1}{m*delta T1} [/latex] [latex]Cw{m delta T1 = delta Q1[/latex] [latex]delta Q1 = 2100 frac{J}{kg*C} * 10kg * 10C[/latex] [latex]delta Q1 = 210000J[/latex] [latex]delta Q2 = Ct*m[/latex] [latex]delta Q2 = 3400[latex]delta Q2 = 3400000J[/latex]00J frac{J}{kg} * 10kg[/latex]