Błagam o pomoc:( Rozwiąż równanie 4 i 2/3 × p = 4 a : 1 i 1/3 = 1/6 Serdecznie Dziękuję:)

[latex]4 frac{2}{3} p=4 \\ frac{14}{3} p=4/* frac{3}{14} \ \ p= frac{12}{14} = frac{6}{7} \ \ Spr.\ 4 frac{2}{3} * frac{6}{7} =4 \\ dfrac{ ot14^2}{3} * dfrac{6}{ ot7^1} =4 \ 4=4 \ L=P \\ \ a:1 frac{1}{3} = frac{1}{6} \ \ a= frac{1}{6} *1 frac{1}{3} \a= dfrac{1}{ ot6^3} * dfrac{ ot4^2}{3} = frac{2}{9} \ \ Spr \ frac{2}{9} :1 frac{1}{3} = frac{1}{6} \ \ frac{2}{9} : frac{4}{3} = frac{1}{6} \ dfrac{ ot2^1}{ ot9^3} *frac{ ot3^1}{ ot4^2} = frac{1}{6} \ \ [/latex] [latex] frac{1}{6} = frac{1}{6} \ L=P[/latex]