1.V - 60km/h1 godzine pokonał - 60km 60:4 = 15 60km +15 km = 75km Odp ;; pokonał drogie 75km 2. v=8000[latex][ frac{m}{s} ][/latex] s= 190000 [m] szukany czas wynosi: t= [latex] [frac{s}{v} ][/latex] = 23,75 [s] 3.Vsr = sc/tcsc - droga całkowita [m]tc - czas całkowity [s] t₁ = 1,5hV₁ = 12km/hs₁ = V₁t₁ = 12*1,5 = 18km s₂ = 20kmV₂ = 16km/ht₁ = s₁/V₁ = 20/16 = 1,25h Vsr = (s₁+s₂)/(t₁+t₂) = (18+20)/(1,25+1,5) = 38/2,75 = 13,81m/s 4. a=delta V/ta= 30-10/5a= 4m/s*2
t = 1, 25 h v = 60 km/h s = vt v = 60 km/h * 1,25h = 75 km 2/ v = 8 km/s s = 190 km czas t = s/v t = 190 km/ 8 km/s = 23,75 s zad 3 t1 = 1,5 h v1 = 12 km/h obl. s1 = v1 * t1 s1 = 12 km/h * 1,5 h = 18 km s2 = 20 km v2 =16 km/h obl. t2 t2 = s2/v2 t2 = 20 km / 16 km/h t2 = 5/4 h = 1 1/4 h v śr = s/t v śr = s1+s2/t1+t2 v śr = 18 km + 20 km / 1,5 h + 1 1/4 h = 38 km / 2 3/4 h = ok.13, 8km/h zad 4 v1 = 10 m/s v2 = 30 m/s t = 5 s a = v2+v1 / t a = 30 - 10 m/s /5s a = 20m/s / 5 s a = 4 m/s2