zad 1 a) 3⁻¹ = 1/3 , 5 ⁻² = (1/5)² = 1/25 , 2⁻³ = (1/2)³ = 1/8 b) (7/11)⁻¹ = 11/7 = 1 4/7 , (1/3)⁻² = 3² = 9 , (3/4)⁻² = (4/3)² = 16/9 = 1 7/9 c) (2,5)⁻¹ = (25/10)⁻¹ = (5/2)⁻¹ = (2/5)¹ = 2/5 (0,4)⁻² = (4/10)⁻² = (2/5)⁻² = (5/2)² = 25/4 = 6 1/4 = 6,25 (1,25)⁻¹ = (125/100)⁻¹ = (5/4)⁻¹ = (4/5)¹ = 4/5 = 0,8 d) (- 10)⁻⁵ = (- 1/10)⁵ = - 1/100000 (- 4)⁻² = (- 1/4)² = 1/16 (- 2)⁻³ = (- 1/2)³ = - 1/8 e) (- 2/3)⁻² = (- 3/2)² = 9/4 = 2 1/4 = 2,25 (- 1/5)⁻³ = (- 5)³ = - 125 (- 3 1/3)⁻⁴ = (- 10/3)⁻⁴ = (- 3/10)⁴ = 81/10000 f) (- 1,2)⁻¹ = (- 12/10)⁻¹ = (- 10/12)¹ = - 10/12 = - 5/6 (- 0,1)⁻⁵ = (- 1/10)⁻⁵ = (- 10)⁵ = - 100000 (- 0,02)⁻⁴ = (- 2/100)⁻⁴ = (- 100/2)⁴ = (- 50)⁴ = 6250000 zad 6 a) 4⁻⁷ * 4⁶ * 4⁻² = 4⁻⁷⁺⁶⁻² = 4⁻³ = (1/4)³ = 1/64 b) 7⁻⁴ : 7⁻³ = 7⁻⁴⁺³ = 7⁻¹ = 1/7 c) (5⁻⁴ * 5³)/5⁻² = 5⁻⁴⁺³/5⁻² = 5⁻¹/5⁻² =5⁻¹⁺² = 5¹ = 5 d) (1/2)⁻³ * 2⁴ = 2³ * 2⁴ = 2³⁺⁴ = 2⁷ = 128
Pomożecie ? Zdj sa w załączniku zad 1,6 daje naj i 10 pkt
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