rozwiaz układ równań metoda podstawiania i przeciwnych współczynników 2(x-y)-10=4 x=-3-y+3(y+1)

Metoda podstawiania [latex] left { {{2(x-y)-10=4} atop {x=mathbf{-3-y+3(y+1)}}} ight. \ \ mathrm{ left { {{2(mathbf{-3-y+3(y+1)}-y)-10=4} atop {x=-3-y+3(y+1)}} ight. } \ \ mathrm{ left { {{2(-3-y+3y+3-y)-10=4} atop {x=-3-y+3(y+1)}} ight. } \ \ mathrm{ left { {{2y-10=4} atop {x=-3-y+3(y+1)}} ight. } \ \ mathrm{ left { {{2y=4+10} atop {x=-3-y+3(y+1)}} ight. } \ \ mathrm{ left { {{2y=14} atop {x=-3-y+3(y+1)}} ight. }[/latex] [latex]mathrm{ left { {{y=7} atop {x=-3-7+3(7+1)}} ight. } \ \ mathrm{ left { {{y=7} atop {x=-10+24}} ight. } \ \ mathrm{ left { {{x=14} atop {y=7}} ight. }[/latex] Metoda przeciwnych współczynników [latex]mathrm{left { {{2(x-y)-10=4} atop {x=-3-y+3(y+1)}} ight. } \ \ mathrm{ left { {{2x-2y-10=4} atop {x=-3-y+3y+3}} ight. } \ \ mathrm{ left { {{2x-2y=4+10} atop {x+y-3y=-3+3}} ight. } \ \ mathrm{ left { {{2x-2y=14 |:(-2)} atop {x-2y=0}} ight. } \ \ mathrm{ left { {{-x+y=-7} atop {x-2y=0}} ight. } \ mathrm{+ \_ \_ \_ \_ \_ \_ \_ \_ \_ \_ \_ } \ mathrm{ -y=-7} \ mathrm{ y=7} [/latex] [latex]mathrm{x-2y=0} \ mathrm{x-2 cdot 7=0} \ mathrm{x-14=0} \ mathrm{x=14} \ \ \ mathrm{ left { {{x=14} atop {y=7}} ight. }[/latex]

Metoda podastawiania 2(x-y)-10=4 x=-3-y+3(y+1) 2x-2y-10=4 x=-3-y+3y+3 2x-2y=14 x=2y 2*2y-2y=14 4y-2y=14 2y=14   /:2 y=7 x=2*7 x=14 Metoda przeciwnych współczynników 2(x-y)-10=4 x=-3-y+3(y+1) 2x-2y-10=4 x=-3-y+3y+3 2x-2y=4+10 x=2y 2x-2y=14 x-2y=0     /*(-1) 2x-2y=14 -x+2y=0 ----------------- x=14 -14+2y=0 2y=14   /:2 y=7