Proszę proszę pomyślcie mi zadanie 7 proszę dam NAJ NAJ NAJ naj naj naj naj

[latex]a) (2x-3)+(3x-4)-(6x+1)=\ =2x-3+3x-4-6x-1=\ =-x-8\ \ \ b) (x^{2}-3x-5)+(2x^{2}+4x+6)+(-x^{2}-x+2)=\ =x^{2}-3x-5+2x^{2}+4x+6-x^{2}-x+2=\ =2x^{2}+3\ \ \ c) (-y^{2}-5y)-(3y^{2}+2y-4)-(7y^{2}+4)=\ =-y^{2}-5y-3y^{2}-2y+4-7y^{2}-4=\ =-11y^{2}-7y\ \ \ d) (2,7x-3,2y+12,5)-(3,8x-2,2y+3,6)+(4,5x+3)=\ =2,7x-3,2y+12,5-3,8x+2,2y-3,6+4,5x+3=\ =3,4x-y+11,9\[/latex] [latex] e) (frac{1}{2}x+3y-5,5)-(frac{3}{4}x-6,5y+7,6)+(2frac{1}{4}x+frac{2}{5}y-8,8)=\ \ =frac{2}{4}x+3y-5,5-frac{3}{4}x+6,5y-7,6+2frac{1}{4}x+frac{4}{10}y-8,8=\ \ =frac{2}{4}x+2frac{1}{4}x-frac{3}{4}x+3y+6,5y+0,4y-21,9=\ \ =2x+9,9y-21,9\ \ \ f) (x^{3}+2y^{2}-1,5)-(3x^{3}-4y^{2}-5)+(2x^{3}-5y^{2}-6,5)=\ =x^{3}+2y^{2}-1,5-3x^{3}+4y^{2}+5+2x^{3}-5y^{2}-6,5=\ =y^{2}-3[/latex]