Rozwiaz rownanie 4x3 + 4x2 - x-1 = 0 pomocy

[latex]4x^{3}+4x^{2}-x-1 = 0\\4x^{2}(x+1) - (x+1) = 0\\(x+1)(4x^{2}-1)=0\\(x+1)(2x+1)(2x-1) = 0\\x+1 = 0 vee 2x+1 = 0 vee 2x-1 = 0\\x = -1 vee 2x = -1 vee 2x = 1\\x = -1 vee x = -frac{1}{2} vee x = frac{1}{2}}[/latex] [latex]x inlbrace-1;-frac{1}{2};frac{1}{2} brace[/latex]

4x³ +4x² -x-1=0 4x²(x+1) -(x+1)=0 (x+1)(4x²-1)=0 (x+1)(2x-1)(2x+1)=0 x= -1    x=1/2     x= -1/2             x∈{-1 ;-1/2 ; 1/2 }