zad. 1 met. podstawiania: a) {x = 5 {3x + y = 17 {x = 5 {3 * 5 + y = 17 =>15 + y = 17 y = 2 {x = 5 {y = 2 b) {x + 3y = 13 {y = 4x {x + 3 * 4x = 13 =>13x = 13 /:13 {y = 4x x = 1 {x = 1 {y = 4 * 1 {x = 1 {y = 4 c) {x = y + 3 {x + 2y = 9 {x = y + 3 {y + 3 + 2y = 9 => 3y = 6 /:3 y = 2 {x = 2 + 3 {y = 2 {x = 5 {y = 2 d) {5x - 2y = 29 {y = x - 4 {5x - 2 * (x - 4) = 29 => 5x - 2x + 8 = 29 {y = x - 4 3x = 21 /:3 x = 7 {x = 7 {y = 7 - 4 {x = 7 {y = 3 e) {x + 2y = 3 => x = 3 - 2y {2x + 5y = 5 {x = 3 - 2y {2(3 - 2y) + 5y = 5 => 6 - 4y + 5y = 5 y = -1 {x = 3 - 2 * (-1) {y = -1 {x = 5 {y = -1 zad. 2 met. przeciwnych współczynników a) {-2x + y = 4 {2x + 2y = 2 => 2x + 2 * 2 = 2 __________ 2x = -2 /:2 3y = 6 /:3 x = -1 y = 2 {x = -1 {y = 2 b) {2x - y = 4 / * 2 {x + 2y = 7 {4x - 2y = 8 {x + 2y = 7 => 3 + 2y = 7 ___________ 2y = 4 /:2 5x = 15 /:5 y = 2 x = 3 {x = 3 {y = 2 zad. 3 (met. podstawiania) {2(x + y) - 3y = 2x + 1 {4x - 3(x + 2y) = 7 - 4y {2x + 2y - 3y = 2x + 1 {4x - 3x - 6y = 7 - 4y {-y = 1 {x - 2y = 7 {y = -1 {x - 2y = 7 {y = -1 {x - 2 * (-1) = 7 => x + 2 = 7 x = 5 {y = -1 {x = 5
prosze o szybka odpowiedz daje naj za wszystkie zadania
rozwiąz metoda podstawiania
{x=5
{3x+y=17
b
{x+3y=13
{y=4x
c)
{x=y+3
{x+2y=9
d)
{5x-2y=29
{y=x-4
e)
{x+2y=3
{2x+5y=5
rozwiąz metoda przeciwnych współczynników (zastosuj do wyznaczenia obu niewiadomych)
{-2x+y=4
[2x+2y=2
b)
{2x-y=4
{x+2y=7
rozwiąz dowolna metodą
{2(x+y)-3y=2x+1
(4x-3(x+2y)=7-4y
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