Rozwiąż rónanie (2x-3)do 2 >-(x+3)(x-3) zad 2 Rozwiąż równanie 9x do 3 -18x do2 +2x-4=0 zad 3 rozłóż wielomian na czynniki -9x do4 -8x do3 +1

[latex]1)\ (2x-3)^2 extgreater -(x+3)(x-3)\ 4x^2-12x+9 extgreater -x^2+9\ 5x^2-12x extgreater 0\ x(5x-12) extgreater 0\ x=0 vee 5x-12=0\ x=0 vee x=frac{12}{5}\ xin (-infty,0)cup (frac{12}{5}. +infty)[/latex] [latex]2)\ 9x^3-18x^2+2x-4=0\9x^2(x-2)+2(x-2)=0\ (9x^2+2)(x-2)=0\ 9x^2+2 = 0 vee x-2=0\ x=o vee x=2\ xin{2}[/latex] [latex]3)\ -9x^4-8x^3+1=-9x^4-9x^3+x^3+1 = \=-9x^3(x+1)+(x+1)(x^2-x+1)=\=(x+1)(-9x^3+x^2-x+1)[/latex]