Oblicz promień 4-tej orbity w atomie wodoru i energie elektronu na tej orbicie ze wzoru : rn=n[2] x r1

[latex]dane:\n = 4\r_1 = 5,3cdot10^{-11} m\E_1 = -13,6 eV\szukane:\r_4 = ?\E_{4} = ?\\Rozwiazanie:\r_{n} = r_1cdot n^{2}\\r_4 = 5,3cdot10^{-11}mcdot4^{2} = 5,3cdot10^{-11}mcdot16\\r_4 = 84,8cdot10^{-11} m = 8,48cdot10^{-10} m[/latex] [latex]E_{n} = E_1cdotfrac{1}{n^{2}}\\E_4 = -13,6eVcdotfrac{1}{4^{2}}=-13,6eVcdotfrac{1}{16}\\E_4 = -0,85 eV\\1 eV = 1,6cdot10^{-19} J\\E_4= -0,85eVcdot1,6cdot10^{-16}frac{J}{eV} = -1,36cdot10^{-19} J[/latex]