Iloczyn pierwiastków wielomianu W(X) = [latex]2[/latex][latex] (x^{2} +3)( x^{2} -2)( x^{2} -9)[/latex] jest równy a -36 b 36 c 54 d 18

[latex]2(x^2+3)(x^2-2)(x^2-9)=0\ x^2+3 =0 ,, vee ,, x^2-2=0 ,, vee ,, x^2-9=0\ x=sqrt{2} ,, vee ,, x=-sqrt{2} ,, vee ,, x=3 ,, vee ,, x=-3\ sqrt{2} cdot (-sqrt{2}) cdot 3 cdot (-3)=(-2) cdot (-9)=18\ oxed{D}[/latex]