Proszę o razwiazanie zadania w załączniku!!!!!!!!

[latex]\P_{ABCD}=P_{Delta ACB}+P_{Delta ACD} \ \ \P_{ABCD}=dfrac{1}{2} cdot|AC|cdot h+dfrac{1}{2} cdot|AC|cdot|BD-h|= \ \ \dfrac{1}{2} |AC|(h+|BD|-h)= dfrac{1}{2} |AC|cdot|BD| \ \ \co nalezalo uzasadnic.[/latex]