Oboicz plis szybko. Zad 4 i 5

Oboicz plis szybko. Zad 4 i 5
Odpowiedź

[latex]4.\dane:\E = 3,2 eV = 3,2cdot1,6cdot10^{-19}J = 5,12cdot10^{-19} J\1 eV = 1,6cdot10^{-19} J\h = 6,63cdot10^{-34} Jcdot s\c = 3cdot10^{8}frac{m}{s}\szukane:\lambda = ?\\Rozwiazanie\E = hcdot f /:h\\f = frac{E}{h} = frac{5,12cdot10^{-19J}}{6,63cdot10^{-34}Jcdot s}} = 0,77cdot10^{15} Hz[/latex] [latex]lambda = frac{c}{f}\\lambda = frac{3cdot10^{8}m/s}{0,77cdot10^{-15}s^{-1}} = 3,896cdot10^{-7} m approx390 nm[/latex] [latex]5.\dane:\m = 8\n = 6\E_1 = -13,6 eV\szukane::\frac{E_6}{E_8}= ?\\Rozwiazanie\\E_{n} = E_1cdotfrac{1}{n^{2}}\\E_8 = -13,6eVcdotfrac{1}{8^{2}} = -frac{13,6eV}{64} = -0,2125 eV\\E_6 = -13,6eVcdotfrac{1}{6^{2}} = -frac{13,6eV}{36} = -0,3778 eV\\frac{E_6}{E_8} = frac{-0,3778eV}{-0,2125eV} approx1,78\\E_6 approx1,78E_8[/latex]

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