Oblicz 4x(3i3/5+2i3/5)= 3i4/5-4/5x1i1/2= (1i1/3+2i5/6):5i5/6-2i1/2)= 2i1/2:1/2+(1i1/2) do potęgi 2= pomóżcie to na jutro pliss Daje naj z góry dzięki 

4x(3i3/5+2i3/5)=  4 * 6 1/5 = 4 * 31/5 = 124/5 = 24 4/5 3i4/5-4/5x1i1/2=  3 4/5 - 4/5 * 3/2 = 3 4/5 - 6/5 = 2 9/5 - 6/5 = 2 3/5 (1i1/3+2i5/6):5i5/6-2i1/2)= ( 2/6 + 2 5/6 ) : ( 5 5/6 - 2 1/2 ) = 3 1/6 : 3 4/6 = 19/6 : 22/6 = 19/6 * 6/22 = 19/22 2i1/2:1/2+(1i1/2) do potęgi 2=2 1/2 : 1/2 + 9/4 = 5/2 * 2/1 + 9/4 = 5 + 9/4 = 5 9/4