Rozwiąże ktoś to równanie? 4² + (1[latex] frac{1}{6} [/latex] )² = a²

4² + (1 1/6)² = a²16 + (7/6)² = a²16 + 49/36 = a²576/36 + 49/36 = a²625/36 = a²  a² - 625/36 = 0(a - 25/6)(a + 25/6) = 0a = 25/6 = 4 1/6  lub  a = -25/6 = -4 1/6    Jeśli a > 0  to a = 4 1/6