Proszę o rozwiązanie, potrzebuje zadania na kartkówkę. A nie idzie mi za dobrze z fizyki.

zad.1. n = 960 t = 1 min = 60 s a) częstotliwość :  f = n/ t f = 960 /60 s = 16 Hz okres obrotu : T = 1 / f T = 1/ 16 Hz = 0,0625 s b) d = 50 cm r = d/2 = 25 cm = 0,25 m V = 2πr / T V = 2 *3,14 * 0,25 m / 0,0625 s = 25,12 m/s c) m = 200 g = 0,2 kg [latex]F_d = frac{mV^2}{r } [/latex] [latex]F_d = frac{0,2 kg * (25,12 frac{m}{s})^2 }{0,25 m } = 504,8 N [/latex] zad.2. t = 1 min = 60 s m = 60 kg r = 12 m F = 60 kg * 10 N/kg = 600 N n = ? [latex]F_d = frac{mV^2}{t } ................ extgreater V = 2 pi rf[/latex] [latex]F_d = frac{m * (2 pi rf)^2}{r } = frac{m*4 pi ^2r^2f^2}{r } = 4m pi ^2rf^2 ... extgreater f = frac{n}{t} [/latex] [latex]F_d = 4m pi ^2r frac{n^2}{t^2} /* t^2 [latex]F_d * t^2 = 4 pi ^2mrn^2 / : 4 pi ^2mr [/latex] [latex]n^2 = frac{F_d * t^2}{4 pi ^2 m r } [/latex] [latex]n = sqrt{ frac{F_d*t^2}{4 pi ^2 mr} } [/latex] [latex]n = sqrt{ frac{600 N * (60 s )^2}{4 * (3,14 )^2*60 kg * 12 m } } = 8,7 [/latex]