Pomocy! 〖log〗_(1/2) (4√8)/∛2 = x sin^4 α+ cos^2 α * sin^2 α + cos^2 α = 1

[latex]\1. \ \log_{ frac{1}{2} } dfrac{4 sqrt{8} }{ sqrt[3]{2}} =x iff ( frac{1}{2} )^x=dfrac{4 sqrt{8} }{ sqrt[3]{2}} \ \ \2^{-x}= dfrac{2^2cdot2^ frac{3}{2} }{2^ frac{1}{3} } \ \ \2^{-x}=2^{ frac{7}{2} - frac{1}{3} } \ \2^{-x}=2^{ frac{21}{6} - frac{2}{6} } \ \ \-x= dfrac{19}{6} \ \ \x=- dfrac{19}{6} [/latex] 2. [latex]\sin^4 alpha +cos^2 alpha cdot sin^2 alpha + cos^2 alpha = 1 \ \L=sin^2 alpha (sin^2 alpha +cos^2 alpha )+cos^2 alpha = \ \sin^2 alpha cdot1+cos^2 alpha =sin^2 alpha +cos^2 alpha =1 \ \L=P[/latex]