Na podstawie wykresu oblicz A)Przyspieszenie B)Drogę po 2 minutach

[latex]a)\a = frac{Delta v}{Delta t}\\Delta v = 60frac{m}{s}\Delta t = 20 s\\a = frac{60frac{m}{s}}{20s} = 3frac{m}{s^{2}}[/latex] [latex]b)\dane:\v_{o} = 0\a = 3frac{m}s^{2}}\t = 2 min =2cdot60s = 120 s\szukane:\s = ?[/latex] [latex]s = frac{1}{2}at^{2}\\s = frac{1}{2}cdot3frac{m}{s^{2}}cdot(120s)^{2} = frac{1}{2}cdot3frac{m}{}s{2}}cdot14400s^{2} = 21 600 m = 21,6 km[/latex]