Proszę o obliczenie zadania, daję naj ! [latex]2* (frac{ sqrt{6} }{3})^{2} - 1 [/latex]

[latex]2*frac{6}{9}-1=frac{12}{9}-1=frac{4}{3}-frac{3}{3}=frac{1}{3}[/latex]

[latex]2*(frac{sqrt{6}}{3})^{2}-1=2*frac{6}{9}-1 = 2*frac{2}{3}-1 = frac{4}{3}-1 = 1frac{1}{3}-1 = frac{1}{3}[/latex]