Bardzo proszę o rozwiązanie tych zadań. 1. Oblicz: [latex]( 3^{7} * 3^{-9}): 3^{-6}= [/latex] [latex] (frac{2}{3}) ^{-2} =[/latex] [latex] (frac{1}{2}) ^{2} = [/latex] 2.Wyłącz czynnik przed nawias: [latex] sqrt{45} =[/latex] [latex] sqrt[3]{54}=

zad1 1) nie wiem 2) [latex]( frac{2}{3 x} )^{-2} [/latex]=[latex] (frac{3}{2} )^{2} [/latex]=[latex] frac{9}{4} [/latex]=2 [latex] frac{1}{4} [/latex] 3)[latex]( frac{1}{2})^{2} [/latex]=[latex] frac{1}{4} [/latex] zad2 1) [latex] sqrt{45} = sqrt{5*9} =3 sqrt{5} [/latex] 2) [latex] sqrt[3]{54} = sqrt[3]{2*27} =3 sqrt[3]{2}[/latex] zad3 1) 15.3 kg= 15300g 2) 2400 dag= 24000g

[latex]1.\\(3^{7}*3^{-9}):3^{-6} = 3^{(7-9)}:3^{-6} = 3^{((-2-(-6))} = 3^{4} = 81\\(frac{2}{3})^{-2}= (frac{3}{2})^{2} = frac{9}{4} = 2frac{1}{4}\\(frac{1}{2})^{2} = frac{1}{4}[/latex] [latex]2.\\sqrt{45} = sqrt{9*5} = sqrt{9}*sqrt{5} = 3sqrt{5}\\sqrt[3]{54} = sqrt[3]{27*2} = sqrt[3]{27}*sqrt[2]{2} = 3sqrt[3]{2}[/latex] [latex]3.\\15,3 kg = 15 300 g = 1,5*10^{4} g\\2400 dag = 24 000 g = 2,4*10^{4} g[/latex]