Oblicz masy cząsteczkowe podanych związków chemicznych: - mCuO = - mFe2O3 = - mNa2CO3 = - mH2SO4 = - mCa(OH)2 = - mFe2(SO3)3 = Proszę o pomoc

mCuO = 64u+16u = 80u mFe2O3 = 2*56u+3*16u = 112u+48u = 160u mNa2CO3 = 2*23u+12u+3*16u = 46u+12u+48u = 106u mH2SO4 = 2*1u+32u+4*16u = 2u+32u+64u = 98u mCa(OH)2 = 40u+2*16u+2*1u = 40u+32u+2u = 74u mFe2(SO3)3 = 2*56u+3*32u+9*16u = 112u+96u+144u = 352u

- mCuO=63,5u+16u=79,5u - mFe2O3=2*56u+3*16u=160u - mNa2CO3=2*23u+12u+3*16u=106u - mH2SO4=2*1u+32u+4*16u=98u - mCa(OH)2=40u+2*16u+2*1u=74u - mFe2(SO3)3=2*56u+3*32u+9*16u=352u