Znajdź niewymierne rozwiazania równania x³-7x²-6x+42=0

[latex]x^3-7x^2-6x+42=0 \x^2(x-7)-6(x-7)=0 \(x^2-6)(x-7)=0 \(x+ sqrt{6})(x- sqrt{6})(x-7)=0 \x+ sqrt{6}=0 quad vee quad x- sqrt{6}=0 quad vee quad x-7=0 \x=- sqrt{6}quad vee quad x= sqrt{6}quad vee quad x=7 \\oxed{x in {- sqrt{6}, sqrt{6},7 }} \\Dla quad x in mathbb{NW} \\oxed{x in {- sqrt{6}, sqrt{6} }}[/latex]

[latex]x^{3}-7x^{2}-6x+42 = 0\\x^{2}(x-7)-6(x-7) = 0\\(x^{2}-6)(x - 7) = 0[/latex] [latex](x + sqrt{6})(x - sqrt{6})(x - 7) = 0\\x = -sqrt{6} vee x = sqrt{6} vee x = 7[/latex] Rozwiązania niewymierne to: -√6  oraz  √6