z podanego wzoru a=x+1/x +b wyznacz x. kreska ukosna to kreska ulamkowa jakby cos .

a = (x + 1) / (x + b)             I * (x + b) a (x + b) = x + 1 ax + ab = x + 1           I - ax - 1 ab - 1 = x - ax ab - 1 = x(1 - a)          I : (1 - a) (ab - 1) / (1 - a) = x a ≠ 1 i x ≠ -b

[latex]a = frac{x+1}{x+b} |*(x+b)\\a(x+b) = x+1\\ax+ab = x+1\\ax-x = 1-ab\\x(a-1) = 1-ab /:(a-1)\\x = frac{1-ab}{a-1}[/latex] [latex]x eq -b\a eq 1[/latex]