Rozwiąż równanie. 2/5(3-x)= -2 2/5 - dwie piąte Proszę o pomoc dam naj!

[latex]frac{2}{5}(3-x)=-2 /*5\2(3-x)=-10\6-2x=-10\-2x=-16\x=8[/latex]

[latex]frac{2}{5}(3-x)=-2\\frac{6}{5}-frac{2}{5}x=-2\\-frac{2}{5}x=-2-frac{6}{5}\\-frac{2}{5}x=-3frac{1}{5}/:(-frac{2}{5})\\x=-frac{16}{5}*(-frac{5}{2})\\x=frac{80}{10}\\x=8[/latex]