oblicz ciśnienie wody h=10m gęstosci=1000kg3

[latex]dane:\h = 10 m\d = 1000frac{kg}{m^{3}}\g = 10frac{N}{m^{2}}\szukane:\p = ?[/latex] [latex]p = d*g*h\\p = 1000frac{kg}{m^{3}}*10frac{N}{kg}*10m = 100 000 frac{N}{m^{2}}\\p = 100 000 Pa = 1000 hPa = 100 kPa = 0,1 MPa[/latex] 1 hPa = 100 Pa 1 kPa = 1000 Pa 1 MPa = 1 000 000 Pa

D: h = 10m, ρ = 1000kg/m³,   Szuk.: p = ? p = ρ*g*h = 1000 * 10 * 10 = 100 000 Pa = 0,1 MPa                      GOTOWE!!!