Proszę pomóżcie mi ! zad.jest w załączniku .Proszę pomocy

zad 1 srednia artmetyczna 1 i 3 da nam wyraz 2 ((m+3)/5 + (3m+29)/35)/2  = (m+5)/7      /* 2 (m+3)/5 + (3m+29)/35 = 2 (m+5)/7        / *35 7(m+3) + (3m+29) = 10(m+5) 7m+21+3m+29= 10m +50 10m + 50 = 10m + 50 L=P zad 2 sinalfa = a/c cosalfa = b/c a^2+b^2=c^2 wiec sinalfa*cosalfa = (a*b)/(a^2+b^2) = (4*7)/(4^2+7^2)=28/(16+49)=28/65

zad 1 srednia artmetyczna 1 i 3 da nam wyraz 2 ((m+3)/5 + (3m+29)/35)/2  = (m+5)/7      /* 2 (m+3)/5 + (3m+29)/35 = 2 (m+5)/7        / *35 7(m+3) + (3m+29) = 10(m+5) 7m+21+3m+29= 10m +50 10m + 50 = 10m + 50 L=P zad 2 sinalfa = a/c cosalfa = b/c a^2+b^2=c^2 wiec sinalfa*cosalfa = (a*b)/(a^2+b^2) = (4*7)/(4^2+7^2)=28/(16+49)=28/65