potrzebuje pilnie Objętość kuli wynosi 4 pi √3 .Oblicz pole powierzchni tej kuli.

[latex]V= frac{4}{3} r^{3} pi [/latex] [latex]frac{4}{3} pi r^{3} = 4 pi sqrt{3} [/latex] /:π [latex]frac{4}{3} r^{3}=4 sqrt{3} /* frac{3}{4} [/latex] [latex] r^{3} = 3 sqrt{3} [/latex] [latex] r^{3} = ( sqrt{3} )^{3} [/latex] [latex]r = sqrt{3} [/latex] Podstawiasz r do wzoru na p kuli [latex]( sqrt{3} )^{2} *4 pi =3*4 pi = 12 pi [/latex]

[latex]V= frac{4}{3} pi r^3 \ V=4 pi sqrt{3} \ frac{4}{3} pi r^3=4 pi sqrt{3} /: frac{4}{3} pi \ r^3=3 sqrt{3} \ r= sqrt[3]{3 sqrt{3}} = sqrt[3]{3 cdot 3^{ frac{1}{2} }} = sqrt[3]{3^{ frac{3}{2} }} =(3^{ frac{3}{2}})^{ frac{1}{2} }=3^{ frac{1}{2} } =sqrt{3} \ \ \ P=4 pi r^2 \ P=4 pi ( sqrt{3} )^2=12 pi \ \ \ Odp.: P=12 pi j^2[/latex]