PROSZE O POMOC ZRÓBCIE MI TYLKO TE ZAZNACZONE RÓWNANIA POTRZEBUJE NA JUTRO, DAJE NAJ

5-6(2x-3)+9(4-x)=3(5x-2)-8(x-2) 5-12x+18+36-9x=15x-6-8x+16 -12x-9x-15x+8x=-6+16-5-18-36 -28x=-49/:-28 x=49/28=1 21/28 5-[(8x+7)-18x]=9x 5-(8x+7-18x)=9x 5-8x-7+18x=9x -8x+18x-9x=-5+7 x=2 (3x+5)(do kwadratu)+(4x+6)(kwadrat)=(5x+6)(kwadrat)+133 9x+25+16x+36=25x+36+133 9x+16x-25x=36+133-25-36 0=108 - sprzeczność

Zad. 3.6 c) [latex]5-6(2x-3)+9(4-x)=3(5x-2)-8(x-2)[/latex] [latex]5-12x+18+36-9x=15x-6-8x+16[/latex] [latex]-21x+59=7x+10[/latex] [latex]-21x-7x=10-59[/latex] [latex]-28x=-49/:(-28)[/latex][latex]5-[(8x+7)-18x]=9x[/latex] [latex]x= frac{49}{28}= frac{7}{4}=1 frac{3}{4} [/latex] Zad. 3.8 c) [latex]5-[(8x+7)-18x]=9x[/latex] [latex]5-(8x+7-18x)=9x[/latex] [latex]5-(7-10x)=9x[/latex] [latex]5-7+10x=9x[/latex] [latex]-2+10x=9x[/latex] [latex]10x-9x=2[/latex] [latex]x=2[/latex] Zad. 3.9 a) [latex](3x+5)^2+(4x+6)^2=(5x+6)^2+133[/latex] [latex]9x^2+30x+25+16x^2+48x+36=25x^2+60x+36+133[/latex] [latex]25x^2+78x+61=25x^2+60x+169[/latex] [latex]25x^2+78x-25x^2-60x=169-61[/latex] [latex]18x=108/:18[/latex] [latex]x= frac{108}{18}=6 [/latex]