proszę o pomoc bardzo szybko nie mam czasu zad 12 i 14

rozwiązanie w załączniku na przykład 1/3 to ułamek

12. [latex]3 frac{1}{3} -frac{2}{3} = 2frac{4}{3}-frac{2}{3} = 2frac{1}{3}\2 frac{3}{5} -frac{4}{5} = 1frac{8}{5}-frac{4}{5} = 1frac{4}{5}\8 frac{4}{7} -frac{6}{7} = 7frac{11}{7}-frac{6}{7} = 7frac{5}{7}\6 frac{5}{9} -frac{8}{9} = 5frac{14}{9}-frac{8}{9} = 5frac{6}{9} = 5frac{2}{3}[/latex] 14.[latex]frac{1}{3} + frac{2}{3} = frac{3}{3} = 1\1 + frac{2}{3} = 1frac{2}{3}\ 1frac{1}{3}- frac{2}{3} = frac{4}{3}- frac{2}{3} = frac{2}{3}\ 1frac{2}{3}+ frac{2}{3} = 1frac{4}{3} = 2frac{1}{3}\frac{5}{3}-frac{2}{3} = frac{3}{3} = 1\2frac{2}{3}-frac{2}{3} = 2\3frac{1}{3}+frac{2}{3}=3frac{3}{3}=4\3frac{1}{3}-frac{2}{3} = 2frac{4}{3}-frac{2}{3}=2frac{2}{3}\\frac{1}{4}+frac{3}{4} = frac{4}{4} = 1\3 - frac{3}{4} = 2frac{1}{4}[/latex] [latex]1frac{2}{4}+frac{3}{4} = 1frac{5}{4} = 2frac{1}{4}\1frac{1}{4}-frac{3}{4} = frac{5}{4}-frac{3}{4} = frac{2}{4} = frac{1}{2}\2frac{3}{4}-frac{3}{4} = 2\3frac{3}{4}+frac{3}{4} = 3frac{6}{4}=4frac{2}{4} = 4frac{1}{2}\frac{3}{4}-frac{3}{4} = 0\2frac{1}{4}-frac{3}{4}=1frac{5}{4}-frac{3}{4} = 1frac{2}{4}=1frac{1}{2}[/latex]