[latex]Dane:\T_p=20[^oC]\T_k=100[^oC]\t=5[min]=300[s]\U=230[V]\I=0,5[A]\C_w=4200[ frac{J}{kgcdot ^oC}] \\Szukane :\m = ? \\Rozwiazanie :\Q=mcdot C_w cdotDelta T o m = frac{Q}{Delta T cdot C_w} = frac{Q}{(T_k-T_p)cdot C_w} \\P = frac{Q}{t} o Q = Pt = Ucdot I cdot t\\\Q = 230cdot 0,5 cdot 300 = 34500[J]\\m = frac{34500}{(100-20)cdot 4200} approx 0,1 [kg] [/latex]
[latex]dane:\T_1 = 20^{o}C\T_2 = 100^{o}C\t = 5 min = 5*60s = 300 s\U = 230 V\I = 0,5 A\C = 4200frac{J}{kg*^{o}C}\szukane:\m = ?[/latex] [latex]W = Q = m*C*(T_2-T_1)\oraz\W = U*I*t\\m*C*(T_2-T_1) = U*I*t /:C(T_2-T_1)\\m = frac{U*I*t}{C(T_2-T_1)}= frac{230V*0,5A*300s}{4200frac{J}{kg*^{o}C}*(100^{o}-20^{o})} = frac{34500}{336000} kg\\m = 0,1027 kgapprox103 g[/latex]
