[latex]Dane:\s_1=1cdot 2=2m^2\s_2=2cdot 3 = 6 m^2\m=2t=2000kg\\Szukane :\p=?\\Rozwiazanie :\p = frac{F_n}{s} = frac{mg}{s} \\p-cisnienie[Pa]\F_n - sila nacisku [N]\s- pole powierzchni [m^2]\m - masa[kg]\g - przeypieszenie grawitacyjne approx 10[ frac{N}{kg}]\\\p_1= frac{2000cdot10}{2} =10000[Pa]=10[kPa]\\p_2= frac{2000cdot10}{6} =3333 frac{1}{3} [Pa] =3 frac{1}{3} [kPa][/latex]
[latex]dane:\m = 2 t = 2 000 kg\S_1 = 1m*2m = 2 m^{2}\S_2 = 2m * 3m = 6 m^{2}\g = 10frac{m}{s^{2}} = 10frac{N}{kg}\szukane:\p_1 = ?\p_2 = ?[/latex] [latex]p = frac{F}{S}\\ale F = m*g = 2000kg*10frac{N}{kg} = 20 000 N\\p_1 = frac{F}{S_1} = frac{20000N}{2m^{2}} = 10 000 Pa = 10 kPa\\p_2 = frac{F}{S_2} = frac{20000N}{6m^{2}} = 3 333,(3) Pa approx3,(3) kPa[/latex]
