1, a)6²×(2/3)³-10¹= b)(1/8)²+4²x (0,5)²= c)6³:(3/2)³x(1/2)= d)√ 2 i 1/4+(0,2)²-79⁰= prosze na jutro tylko szybko i z góry fenx :)

1, a)6²×(2/3)³-10¹= b)(1/8)²+4²x (0,5)²= c)6³:(3/2)³x(1/2)= d)√ 2 i 1/4+(0,2)²-79⁰= prosze na jutro tylko szybko i z góry fenx :)
Odpowiedź

a) =36*4/9*10=4 b) =1/64+4= 4 1/64 c) =216:27/8*0,5=27:27*0,5 d)

1, a)6²×(2/3)³-10¹= = 36 *8/27 - 10= = 32/3 - 10 = = 10⅔ -10 = = 2/3 b)(1/8)²+4²x (0,5)²= = 1/64 + 16 *1/4= = 1/64 + 4 = = 4 i 1/64 c)6³:(3/2)³x(1/2)= = 216 :(27/8)*(1/2)= = 216*(8/27)*(1/2)= = 96/3= =32 d)√ 2 i 1/4+(0,2)²-79⁰= = √(9/4) + 0,04 - 1= = 3/2 + 0,04 -1= = 1,5 + 0,04 -1 = = 0,54

a)6²×(2/3)³-10¹=36*8/27-10=32/3-10=10 2/3 -10=2/3 b)(1/8)²+4²x (0,5)²=1/64+16*1/4=1/64+4=4 1/64 c)6³:(3/2)³x(1/2)=216:27/8*1/2=216/1*8/27*1/2=108/1*8/27=32 d)√ 2 i 1/4+(0,2)²-79⁰=√ 2 i 1/4+4/100- 1 = √9/4+4/100-1= 3/2+4/100-1=150/100 +4/100-1=54/100=27/50

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