[latex] frac{ sqrt{ sqrt{3} + sqrt{2} }-sqrt{ sqrt{3} -sqrt{2} } }{sqrt{ sqrt{3} + sqrt{2} }+sqrt{ sqrt{3} -sqrt{2} }} = frac{ sqrt{ sqrt{3} + sqrt{2} }-sqrt{ sqrt{3} -sqrt{2} } }{sqrt{ sqrt{3} + sqrt{2} }+sqrt{ sqrt{3} -sqrt{2} }} * frac{ sqrt{ sqrt{3} + sqrt{2} }-sqrt{ sqrt{3} -sqrt{2} } }{sqrt{ sqrt{3} + sqrt{2} }-sqrt{ sqrt{3} -sqrt{2} }}=\ \[/latex] [latex]= frac{ (sqrt{ sqrt{3} + sqrt{2} }-sqrt{ sqrt{3} -sqrt{2} } )^2 }{(sqrt{ sqrt{3} + sqrt{2} }+sqrt{ sqrt{3} -sqrt{2} })(sqrt{ sqrt{3} + sqrt{2} }-sqrt{ sqrt{3} -sqrt{2} })} =\ \ =frac{sqrt{3}+sqrt{2}-2sqrt{(sqrt{3}+sqrt{2})(sqrt{3}-sqrt{2})}+sqrt{3}-sqrt{2}}{sqrt{3}+sqrt{2}-(sqrt{3}-sqrt{2})}\ \ [/latex] [latex]=frac{2sqrt{3}-2sqrt{3-2}}{sqrt{3}+sqrt{2}-sqrt{3}+sqrt{2}}=frac{2sqrt{3}-2sqrt{1}}{2sqrt{2}}=frac{2sqrt{3}-2}{2sqrt{2}}=frac{sqrt{3}-1}{sqrt{2}} approx 0,52[/latex]
[latex]Która liczba jest większa x=frac{sqrt[3]{-27}}{9} czy y=-(frac{10}{3})^{-1} \ Rozwiąż zadania i uzasadnij. [/latex]...
