Rozwiąż równanie : a) [latex] frac{3x-9}{x-3} =2x [/latex]

3x-9 / x-3 = 2x2x(x-3)=3x-92x²-6x=3x-92x²-9x+9=0Δ=b²-4ac=(-9)²-4*2*9=81-72=9√Δ=√9=3x1= -b-√Δ / 2a = 9-3/4=6/4=3/2x2= -b+√Δ/2a = 9+3/4=12/4=3 ∉ D bo x-3=0     x=3

[latex] mathrm{D=mathbb{R}-{3}} \ \ mathrm{mathrm{ frac{3x-9}{x-3} =2x }} \ \ mathrm{mathrm{ frac{3(x-3)}{x-3} =2x }} \ \ mathrm{3=2x |:2} \ \ mathrm{x= frac{3}{2} in D} \ \ \ mathbf{Rozwiazanie: x= frac{3}{2} }[/latex]