rozwiąż równianie : [latex] frac{2x^2-x-3}{x+1} =1 [/latex]

[latex]frac{2x^2-x-3}{x+1} =1\ D=R/{-1}\ 2x^2-x-3=x+1\ 2x^2-2x-4=0\ delta=4-4*2*(-4)\ delta=36\ x_1= frac{2+6}{4} =2 \ x_2= frac{2-6}{4} =-1[/latex] x2∉D

[latex]\ frac{2x^2-x-3}{x+1} =1 /*(x+1) , x eq -1 \ \2x^2-x-3=x+1 \ \2x^2-2x-4 =0/:2 \ \x^2-x-2=0 \ \x^2+x-2x-2=0 \ \x(x+1)-2(x+1)=0 \ \(x+1)(x-2)=0 \ \x=-1 otin D vee x=2 \ \Odp. x=2[/latex]