zadanie108 plis na na dzisiaj

|AB| = |CD| = 10 cm |BC| = |AD| = 5 cm Pole prostokąta ABCD P: P = |AB|*|CD| = 10*5 = 50 cm^2 P1 = x - pole mniejszego prostokata ( EBCF) P2 = x+20 - pole większego prostokata (AEFD) x+ x+20 = 50 2x = 30  |:2 x = 15 cm^2 P2 = x+20 = 15 + 20 = 35 cm^2 P2 = |AE|*|AD| 35 = |AE|*5  |:5 |AE| = 7 cm