prosze o pomoc w rozwiązaniu równanai a) x-(2x-4)=3x+(x-1)= i jeszcze b) 3(x+1)-2(x+2)=6-(2x+4)= c) 5-(x+3)=4-(x-1)+(2x+1)= d) 4(2x+2)-3(2x+3=5x+2= prosze pomuście pilnie

a) x - (2x - 4) = 3x + (x - 1) x - 2x + 4 = 3x + x - 1 - 5x = - 5 / : (- 5) x = 1 b) 3(x + 1) - 2(x + 2) = 6 - (2x + 4) 3x + 3 - 2x - 4 = 6 - 2x - 4 3x = 3 / : 3 x = 1 c) 5 - (x + 3) = 4 - (x - 1) + (2x + 1) 5 - x - 3 = 4 - x + 1 + 2x + 1 - 2x = 4 / : (- 2) x = - 2 d) 4(2x + 2) - 3(2x + 3) = 5x + 2 8x + 8 - 6x - 9 = 5x + 2 - 3x = 3 / : (- 3) x = - 1

a) x-(2x-4)=3x+(x-1) x-2x+4=3x+x-1 x-2x-3x-x=-1-4    -5x= -5/:(-5)      x=1 b). 3(x+1)-2(x+2)=6-(2x+4) 3x+3-2x-4=6-2x-4 3x-2x+2x=6-4+4-3    3x=3/:3      x=1 c) 5-(x+3)=4-(x-1)+(2x+1) 5-x-3=4-x+1+2x+1 -x+x-2x=1+1+4+3-5    -2x=4/:(-2)      x= -2 d) 4(2x+2)-3(2x+3)=5x+2 8x+8-6x-9=5x+2 8x-6x-5x=2+9-8    -3x=3/:(-3)      x= -1