jak obliczyc(pierw z 6p+pierw z 15q)do2  ???

[latex](a+b)^{2} = a^{2}+2ab+b^{2}[/latex] [latex](sqrt{6p} + sqrt{15q})^{2} = (sqrt{6p})^{2}+2*sqrt{6p*15q}+(sqrt{15q})^{2}=\\=6p+2*sqrt{90pq} + 15q = 6p + 2*sqrt{9*10pq}+15q=\\=6p+2*sqrt{9}*sqrt{10pq}+15q=6p+2*3*sqrt{10pq} + 15q=\\=6p+6sqrt{10pq}+15q[/latex]