Zawartosc procentowa pierwiastkow w: 1.siarczek magnezu 2.azotan (V) magnezu 3.octan metylu 4.sacharoza 5.kwas mrowkowy

1) mMgS=24u+32u=56u %Mg = (24/56)*100% = 42,86% %S = (32/56)*100% = 57,14% 2) mMg(NO₃)₂=24u+28u+96u=148u %Mg = (24/148)*100% = 16,22% %N = (28/148)*100% = 18,92% %O = (96/148)*100% = 64,86% 3) mC₃H₆O₂=36u+6u+32u=74u %C = (36/74)*100% = 48,65% %H = (6/74)*100% = 8,11% %O = (32/74)*100% = 32,24% 4) mC₁₂H₂₂O₁₁=144u+22u+176u=342u %C = (144/342)*100% = 42,11% %H = (22/342)*100% = 6,43% %O = (176/342)*100% = 51,46% 5) mCH₂O₂=12u+2u+32u=46u %C = (12/46)*100% = 26.09% %H = (2/46)*100% = 4,35% %O = (32/46)*100% = 69,56%