Rozwiaz nierownosc (x-2)2+(2x+1)2/>(2pierwiastek2-4)(2pierwiastek2+4)+33

[latex]\(x-2)^2+(2x+1)^2 geq (2 sqrt{2} -4)(2 sqrt{2} +4)+33 \ \x^2-4x+4+4x^2+4x+1 geq 4*2-16+33 \ \5x^2+5 geq 25/:5 \ \x^2+1 geq 5 \ \x^2-4 geq 0 \ \(x+2)(x-2) geq 0 \ \xin (-infty,-2 extgreater cup extless 2,+infty)[/latex]