5xdo2 - 2x = 1 - 6xdo3 proszę o pomoc :)

6x³ + 5x² - 2x -1=0 6x²(x+1)-x(x+1)-(x+1)=0 (x+1)(6x²-x-1)=0 (x+1)(6x²-3x+2x-1)=0 (x+1)*[3x(2x-1)+(2x-1)]=0 (x+1)(2x-1)(3x+1)=0 x+1=0  v  2x-1=0  v  3x+1=0 x∈{-1, -1/3, 1/2}