Zad1 Rozwiąz równania pls dam naj pls y+3/2-(1-y)=3,5 1/2(y-3)-2/3(y-3/5)+1/3=2/5-1/3(2y-3)

y+3/2-(1-y)=3,5y+ 1,5 -1+y= 3,52y= 3y= 1,5zad2) 1/2(y-3)-2/3(y-3/5)+1/3=2/5-1/3(2y-3) 1/2y-3/2-2/3y+ 2/5+ 1/3= 2/5-2/3y+11/2y-2/3y+2/3y= 1,5-2/5-1/3+2/5+11/2y= 5/2-1/3 1/2y= 15/6- 5/151/2y= 10/6y=10/3 = 3 1/3