Proszę o pomoc w rozwiązaniu zadani. Pilne!!!!!! Zad 1 4x-1 --------< 5 3 Zad 2 3(2x-7)-(7x-13)>-10 Zad 3 Doprowadź do najprostszej postaci (2x-3)²-(x²+16+8x)

1.(4x-1) /3 < 5 4x-1<15 4x<16 x<4 2. 3(2x-7)-(7x-13)>-10    6x-21-7x+13>-10    -x>-2    x<2 3. 4x²-12x+9-x²-16-8x=3x²-20x-7

[latex] frac{4x-1}{3} <5 / cdot 3[/latex] [latex]4x-1 <15[/latex] [latex]4x <15+1[/latex] [latex]4x <16 /:4[/latex] [latex]x<4[/latex] ====================== [latex]3(2x-7)-(7x-13)>-10[/latex] [latex]6x-21-7x+13>-10[/latex] [latex]6x-7x>-10+21-13[/latex] [latex]-x>-2 /:(-1)[/latex] [latex]x<2[/latex] ====================== [latex](2x-3)^2-(x^2+16+8x)=4x^2-12x+9-x^2-16-8x=3x^2 - 20x - 7[/latex]