oblicz granicę: lim x-> -3 x2+4x+3 / x2-9 x2- to x do kwadratu

[latex]\ lim_{x o -3} frac{x^2+x+3x+3}{(x+3)(x-3)} = lim_{x o-3} frac{(x+3)(x+1)}{((x+3)(x-3)} = \ \ lim_{x o -3} frac{x+1}{x-3} = frac{-3+1}{-3-3} = frac{1}{3} [/latex]